Jason: [Let x = job to be done; y=rate of doing the job => Time to complete job = x/y

If product run 50% faster; �new y� = 1.5y
Time to complete job = x/(1.5y) [Save 33% of time]
If product run 150% faster, �new y� = 2.5y
Time to complete job = x/(2.5y) [Save 60% of time]
No back to yesterday!]

Wilson: [這是一個小學的正比例及反比例問題，一位工人要一天完成的工作，兩位工人只需半天，如此類推：

This is a primary school scale problem, one worker need one day to finish, two workers need half day and etc.

1 worker :1   day
2 workers:1/2 day
3 workers:1/3 day

現在研究我們的問題： now lets plug into our problem:

100MHz computer:1    second
150MHz computer:0.66 second <-- in  50% faster, 1/(150/100)
250MHz computer:0.4  second <-- in 150% faster, 1/(250/100)

問題開始時以百分比來混淆了思維，再以50%:50%之正比例來錯誤引導，也許各位也確曾看過類似廣告，快了百分之五十，事實才省了百分之三十三的時間，並非百分之五十。

At the beginning, the question used percentage to confuse you, and then quoted "adobe's" 50%:50% incorrect scale. You may actually saw such advertisement before. Actually, 50% faster can only save 33% of time.]