Wilson: [Lets recall the definition of derivative:

The trick is that x²=x+x+x+...+x (x-times) but couldn't be derivative since the right hand side require x=>1 and must be a real number. Therefore cannot approach to 0 (not even close). Otherwise, it won't be equal to x². ]

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Jason: [At the left-hand side of 2^nd equation, the first x is a constant while the second x is a variable. So the derivative of xx with respect to x should be x instead of 2x.]

Wilson:[I couldn't agree with you. The xx, the first one and the latter one is still variable.  When x=3=>3+3+3 (3-times) and when x=4=>4+4+4+4 (4-times) and etc. As long as it is variable, it still stands legal and could be derivative. ]